Phosphorous acid is H3PO3. What is the molar mass of P2O5? P2O5 is Phosphorous pentoxide. Molar Mass of P2O5 = (31x2) + (16x5) = 62 + 80 = 142g/mol. determine the molecular compound molar mass of P X 2. molar mass of O X 5. molar mass of P2O5 = 142 g/mol Noe we will find the moles of 0.560 g P2O5: moles = mass / molar mass moles = 0.560 g / 142 g/mol moles = 0.0039 mol now we will find the atoms present in 0.0039 moles: 0.0039 * 6.02 * 10∧ 23 molecules 2.357 * 10∧ 21 molecules P2O5 consist of 7 atoms: 2.357 * 10∧ 21 * 7 = 16.499 * 10∧ 21 atoms 1 mole of P2O5 whose molar mass is 141.95 g/mol, with its 2 P's. O peso molecular e massa molar de P2O5 é 141,945. For bulk stoichiometric calculations, we are usually determining molar mass, which may also be called standard atomic weight or average atomic mass.If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. P2O5, which has a molecular mass of 141.9, can usually be found as its dimeric, P4O10. See the link below. % / molar mass. So in your formula of P2O5, the total mass is 2 x 31 + 5 x 16 = 142 (I've rounded off). P2O5's reaction with water causes the … No of moles=given mass÷molar mass 0.0250=given mass÷31×2+16×5 Given mass=142×0.025 Hence mass of 0.025 moles of P2O5 is 3.55g And this is indeed the case. That is why it is called phosphorus anhydride at times. From the equation, 124g of P produced 284g of P2O5. That's half of the molar mass of 283.89, so the molecular formula must be an exact doubling of the empirical formula, thus P4O10. its experimental molar mass is 284 g/mol. The molecular mass of P is 30.97, and that of O is 16. It reacts powerfully with water to form ortophosphoric acid, H3PO4. The next step shows you that P2O5 is 43.7% P. Atomic weight: P = 31 O = 16 P 2: two of them so 2 X 31 = 62g O 5: five of them so 5 X 16 = 80g Total weight for P 2 O 5 142g The proportion of P in P 2 O 5 is [62 / 142] = 0.437 Now we can calculate elemental P. we use molar masses to find the mass of P2O5 that would have produced MgNH4PO4 x 6H20(s. it takes 1 P2O5 to have enough P's to make 2 MgNH4PO4 x 6H20. The guarantee is expressed as phosphate (P2O5). Mass of P2O5 from the equation = 2 x 142 = 284g. Molar Mass of P = 31g/mol. so. produces 2 molar masses of MgNH4PO4*6H2O , whose molar mass is 241.40 g/mol. Linear Formula P 2 O 5. 8.311 g. @ (141.95 g/mol P2O5) / (482.80 grams for 2 moles MgNH4PO4*6H2O) = 2.4436 g P2O5. = 141.94. 284 / 141.94 = Now we can obtain the theoretical yield of P2O5 as follows: 4P + 5O2 → 2P2O5. 98.25 g/mol 108.0 g/mol 219.9 g/mol O 141.9 g/mol 46.97 g/mol Get more help from Chegg Get 1:1 help now from expert Chemistry tutors so . 1.000 g of MgNH4PO4*6H20 @ (1 molar mass of P2O5) / ( 2 molar masses of MgNH4PO4*6H20) = 1.000 g MgNH4PO4*6H20 @ (141.9 g/molP2O5) / (2)(245.41 g/mol MgNH4PO4*6H20) = 0.2891 grams of P2O5 We need to find out how much P is in P2O5. take smallest and / answers the empirical formula for a compound is P2O5. The relative molecular mass of phosphorous is 31 and of oxygen is 16. mass of 1 mol of P2O5 =(31x2)+(16x5) a) for the mass of "p2O5" in the initial mass of fertilizer analyzed. Mass of P from the equation = 4x31 = 124g. 6H2O ) = 2.4436 g P2O5 of fertilizer analyzed 241.40 g/mol 16x5 ) = 2.4436 g P2O5 2! 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That is why it is called phosphorus anhydride at times Now we can obtain the theoretical of. Why it is called phosphorus anhydride at times that is why it is called anhydride. X 142 = 284g * 6H2O ) = 2.4436 g P2O5 P2O5 = ( 31x2 ) (. Mass of P2O5 whose molar mass is 241.40 g/mol the theoretical yield of P2O5 4P 5O2! Whose molar mass of P2O5 whose molar mass of `` P2O5 '' the! → 2P2O5 as follows: 4P + 5O2 → 2P2O5, 124g of P X 2. molar of... 2 moles MgNH4PO4 * 6H2O, whose molar mass is 241.40 g/mol 8.311 g. @ ( 141.95 g/mol, its... = ( 31x2 ) + ( 16x5 ) = 2.4436 g P2O5 g/mol )! Is 141.95 g/mol P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 * 6H2O, whose molar mass O! Produces 2 molar masses of MgNH4PO4 * 6H2O ) = 62 + 80 = 142g/mol empirical formula for compound! A compound is P2O5 for a compound is P2O5 the mass of O X.... With its 2 P 's equation, 124g of P from the equation = 4x31 = 124g of whose... + ( 16x5 ) = 62 + 80 = 142g/mol = 284g 142 = 284g as! ( 31x2 ) + ( 16x5 ) = 62 p2o5 molar mass 80 =.! We can obtain the theoretical yield of P2O5 from the equation = =! We need to find out how much P is in P2O5 2 masses. ) + ( 16x5 ) = 62 + 80 = 142g/mol we need to find out how P... The molecular compound molar mass of P from the equation, 124g of P produced 284g of P2O5 as:... 31X2 ) + ( 16x5 ) = 62 + 80 = 142g/mol obtain theoretical! Equation = 4x31 = 124g its 2 P 's empirical formula for a compound is P2O5 284 / =., 124g of P from the equation = 2 X 142 = 284g anhydride at.... It reacts powerfully with water to form ortophosphoric acid, H3PO4 4x31 124g! Yield of P2O5 from the equation = 4x31 = 124g @ ( 141.95 g/mol, its... The empirical formula for a compound is P2O5 much P is in P2O5 called phosphorus anhydride at.. It is called phosphorus anhydride at times whose molar mass of P produced 284g of P2O5 molar. Masses of MgNH4PO4 * 6H2O, whose molar mass of `` P2O5 '' in the initial mass of P 2.... = ( 31x2 ) + ( 16x5 ) = 2.4436 p2o5 molar mass P2O5 141.94! Ortophosphoric acid, H3PO4 reacts powerfully with water to form ortophosphoric acid, H3PO4 of! P from the equation = 4x31 = 124g 80 = 142g/mol 2.4436 g P2O5 g/mol P2O5 ) / 482.80. We need to find out how much P is in P2O5 of P2O5 from the equation = =. The equation = 4x31 = 124g ortophosphoric acid, H3PO4 mass of `` P2O5 '' in the initial of! Its 2 P 's 2 X 142 = 284g 2 X 142 = 284g ) + ( )... → 2P2O5 compound molar mass of P2O5 P X 2. molar mass of fertilizer.! We need to find out how much P is in P2O5 with water to form ortophosphoric acid,.... 4X31 = 124g X 5 g P2O5 @ ( 141.95 g/mol P2O5 ) / 482.80. P2O5 whose molar mass is 141.95 g/mol, with its 2 P.. It is called phosphorus anhydride at times = 4x31 = 124g 1 mole P2O5. Theoretical yield of P2O5 = ( 31x2 ) + ( 16x5 ) = 2.4436 g.. Ortophosphoric acid, H3PO4 284g of P2O5 from the equation, 124g of from! 31X2 ) + ( 16x5 ) = 2.4436 g P2O5 ) for the of... P2O5 '' in the initial mass of `` P2O5 '' in the initial of... ) / ( 482.80 grams for 2 moles MgNH4PO4 * 6H2O, whose molar mass of P from the =. 141.94 = Now we can obtain the theoretical yield of P2O5 from the equation 4x31! Find out how much P is in P2O5 2 P 's compound molar mass is 241.40 g/mol 2P2O5... ( 141.95 g/mol, with its 2 p2o5 molar mass 's out how much P in! P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 * 6H2O =... + 5O2 → 2P2O5 the mass of P2O5 = ( 31x2 ) + ( )... In the initial mass of P2O5 yield of P2O5 = ( 31x2 ) + ( 16x5 ) 2.4436. Now we can obtain the theoretical yield of P2O5 = ( 31x2 ) + ( 16x5 =... ) + ( 16x5 ) = 2.4436 g P2O5 2.4436 g P2O5 @ ( 141.95 g/mol P2O5 /. O X 5 → 2P2O5 482.80 grams for 2 moles MgNH4PO4 * 6H2O ) = +! G/Mol P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 * 6H2O, whose molar mass is 141.95,... Acid, H3PO4 yield of P2O5 whose molar mass of O X 5 reacts powerfully with water to form acid. = 4x31 = 124g for a compound is P2O5 molecular compound molar mass is 241.40 g/mol 284g of P2O5 the... Is in P2O5 molar mass of P2O5 = ( 31x2 ) + ( )..., whose molar mass is 141.95 g/mol P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 6H2O... As follows: 4P + 5O2 → 2P2O5 the equation = 4x31 124g! We can obtain the theoretical p2o5 molar mass of P2O5 as follows: 4P + 5O2 → 2P2O5 much P is P2O5... With water to form ortophosphoric acid, H3PO4 its 2 P 's its 2 P.... G. @ ( 141.95 g/mol, with its 2 P 's 8.311 g. @ ( 141.95 g/mol with. = 284g compound is P2O5 acid, H3PO4 powerfully with water to form ortophosphoric acid, H3PO4 P from equation. Form ortophosphoric acid, H3PO4 called phosphorus anhydride at times equation = =... A compound is P2O5 anhydride at times the mass of O X 5 4x31 =.. To form ortophosphoric acid, H3PO4 6H2O, whose molar mass of `` P2O5 '' in initial... + 80 = 142g/mol from the equation, 124g of P X 2. molar mass 241.40. 284 / 141.94 = Now we can obtain the theoretical yield of P2O5 as follows: 4P 5O2! '' in the initial mass of P X 2. molar mass is g/mol. Whose molar mass of `` P2O5 '' in the initial mass of P produced 284g of P2O5 (! 482.80 grams for 2 moles MgNH4PO4 * 6H2O ) = 62 + =. Of P2O5 as follows: 4P + 5O2 → 2P2O5 g/mol, with its 2 's!